Question

Find the discriminant.
8t2+8t+2=0

Answer 1

To find the discriminant of the quadratic equation \( 8t^2 + 8t + 2 = 0 \), we use the formula for the discriminant given by:

\[
D = b^2 - 4ac
\]

In this case, the coefficients \( a \), \( b \), and \( c \) are as follows:

- \( a = 8 \)
- \( b = 8 \)
- \( c = 2 \)

Now, we substitute these values into the formula:

\[
D = 8^2 - 4 \cdot 8 \cdot 2
\]
\[
D = 64 - 64
\]
\[
D = 0
\]

The discriminant of the quadratic equation \( 8t^2 + 8t + 2 = 0 \) is \( D = 0 \). This means that the equation has one real double root.