To solve the expression \( 40 \cdot 5^{-2} \cdot (-2)^{-3} \) using the properties of integer exponents, we start by rewriting the parts that have negative exponents.
- Rewriting with Positive Exponents:
- The term \( 5^{-2} \) can be rewritten as \( \frac{1}{5^2} \).
- The term \( (-2)^{-3} \) can be rewritten as \( \frac{1}{(-2)^3} \).
Thus, we have:
\[ 40 \cdot 5^{-2} \cdot (-2)^{-3} = 40 \cdot \frac{1}{5^2} \cdot \frac{1}{(-2)^3} \]
Now substitute \( 5^2 = 25 \) and \( (-2)^3 = -8 \):
\[ 40 \cdot \frac{1}{25} \cdot \frac{1}{-8} \]
- Combining the Expressions: Now we combine the fractions:
\[ 40 \cdot \frac{1}{25} \cdot \frac{1}{-8} = \frac{40}{25} \cdot \frac{1}{-8} \]
- Calculating \( \frac{40}{25} \):
\[ \frac{40}{25} = \frac{8}{5} \]
Now we can plug this into the expression:
\[ \frac{8}{5} \cdot \frac{1}{-8} = \frac{8}{5} \cdot \frac{1}{-8} = \frac{8}{-40} = \frac{-1}{5} \]
- Final Answer:
Thus, the simplified fraction with no remaining exponents is:
\[ \boxed{-\frac{1}{5}} \]