Determine the oxidation number of each atom in the following substances

NF3: N__ F__
K2CO3: K__ C__ O__
HlO4: H__ I__ O__
Br2: Br__
2Nal: Na__ l__
I2: I__
2NaBr: Na__ Br__
Fe2O3: Fe__ O__
2Al: Al__
Al2O3: Al__ O__
2Fe: Fe__

1 answer

To determine the oxidation numbers of each atom in the given substances, we will follow standard rules for assigning oxidation states. Let's go through each substance one by one:

NF3

  • N: +3 (Nitrogen is less electronegative than fluorine)
  • F: -1 (Fluorine always has an oxidation state of -1)

K2CO3

  • K: +1 (Potassium is an alkali metal, typically +1)
  • C: +4 (In carbonate, C is typically +4)
  • O: -2 (Oxygen usually has an oxidation state of -2)

HIO4

  • H: +1 (Hydrogen is usually +1)
  • I: +7 (For Iodine in peroxides due to 4 O's, resulting in +7 total to balance for -8 from O)
  • O: -2 (Oxygen usually has an oxidation state of -2)

Br2

  • Br: 0 (In elemental form, the oxidation state is 0)

2NaI

  • Na: +1 (Sodium is an alkali metal, usually +1)
  • I: -1 (Iodine in compounds is often -1, especially in ionic form like iodide)

I2

  • I: 0 (In elemental form, the oxidation state is 0)

2NaBr

  • Na: +1 (Sodium is an alkali metal, usually +1)
  • Br: -1 (Bromine is typically -1 in ionic compounds)

Fe2O3

  • Fe: +3 (Iron in this oxide is typically in the +3 state)
  • O: -2 (Oxygen usually has an oxidation state of -2)

2Al

  • Al: 0 (In elemental form, the oxidation state is 0)

Al2O3

  • Al: +3 (Aluminum in this oxide is typically +3)
  • O: -2 (Oxygen usually has an oxidation state of -2)

2Fe

  • Fe: 0 (In elemental form, the oxidation state is 0)

Summary:

  • NF3: N +3, F -1
  • K2CO3: K +1, C +4, O -2
  • HIO4: H +1, I +7, O -2
  • Br2: Br 0
  • 2NaI: Na +1, I -1
  • I2: I 0
  • 2NaBr: Na +1, Br -1
  • Fe2O3: Fe +3, O -2
  • 2Al: Al 0
  • Al2O3: Al +3, O -2
  • 2Fe: Fe 0
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