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The length of a rectangular garden is given by the function f(x)=x+4 . The width of a rectangular garden is given by the functi...Asked by s4t4n45
The length of a rectangular garden is given by the function f(x)=x+4
. The width of a rectangular garden is given by the function g(x)=2x−1
. What function represents the area of the rectangular garden? What is the domain?(1 point)
Responses
(f⋅g)(x)=3x+3
and the domain of (f⋅g)(x)
is (−∞,∞)
.
open paren f times g close paren of x is equal to 3 x plus 3 and the domain of open paren f times g close paren of x is open paren negative infinity comma infinity close paren .
(f⋅g)(x)=3x+3
and the domain of (f⋅g)(x)
is x≥12
.
open paren f times g close paren of x is equal to 3 x plus 3 and the domain of open paren f times g close paren of x is x is greater than or equal to 1 half .
(f⋅g)(x)=2x2+7x−4
and the domain of (f⋅g)(x)
is (−∞,∞)
.
open paren f times g close paren of x is equal to 2 x squared plus 7 x minus 4 and the domain of open paren f times g close paren of x is open paren negative infinity comma infinity close paren .
(f⋅g)(x)=2x2+7x−4
and the domain of (f⋅g)(x)
is x≥12
.
. The width of a rectangular garden is given by the function g(x)=2x−1
. What function represents the area of the rectangular garden? What is the domain?(1 point)
Responses
(f⋅g)(x)=3x+3
and the domain of (f⋅g)(x)
is (−∞,∞)
.
open paren f times g close paren of x is equal to 3 x plus 3 and the domain of open paren f times g close paren of x is open paren negative infinity comma infinity close paren .
(f⋅g)(x)=3x+3
and the domain of (f⋅g)(x)
is x≥12
.
open paren f times g close paren of x is equal to 3 x plus 3 and the domain of open paren f times g close paren of x is x is greater than or equal to 1 half .
(f⋅g)(x)=2x2+7x−4
and the domain of (f⋅g)(x)
is (−∞,∞)
.
open paren f times g close paren of x is equal to 2 x squared plus 7 x minus 4 and the domain of open paren f times g close paren of x is open paren negative infinity comma infinity close paren .
(f⋅g)(x)=2x2+7x−4
and the domain of (f⋅g)(x)
is x≥12
.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find the function that represents the area of the rectangular garden, we need to multiply the functions \( f(x) \) and \( g(x) \):
1. **Finding the functions:**
- Length: \( f(x) = x + 4 \)
- Width: \( g(x) = 2x - 1 \)
2. **Function for area:**
\[
A(x) = f(x) \cdot g(x) = (x + 4)(2x - 1)
\]
3. **Expanding:**
\[
A(x) = x(2x) + x(-1) + 4(2x) + 4(-1) = 2x^2 - x + 8x - 4 = 2x^2 + 7x - 4
\]
So, the function that represents the area of the rectangular garden is:
\[
(f \cdot g)(x) = 2x^2 + 7x - 4
\]
4. **Finding the domain:**
Since the length \( f(x) = x + 4 \) must be greater than zero for the garden to have a physical meaning (length cannot be negative), we solve:
\[
x + 4 > 0 \implies x > -4
\]
The width \( g(x) = 2x - 1 \) similarly must be positive:
\[
2x - 1 > 0 \implies 2x > 1 \implies x > \frac{1}{2}
\]
The more restrictive condition is \( x > \frac{1}{2} \).
Thus, we can determine that the area function \( (f \cdot g)(x) = 2x^2 + 7x - 4 \) has the domain:
\[
\text{Domain: } x > \frac{1}{2}
\]
So, the complete result is:
\[
(f \cdot g)(x) = 2x^2 + 7x - 4 \quad \text{and the domain of } (f \cdot g)(x) \text{ is } x > \frac{1}{2}.
\]
1. **Finding the functions:**
- Length: \( f(x) = x + 4 \)
- Width: \( g(x) = 2x - 1 \)
2. **Function for area:**
\[
A(x) = f(x) \cdot g(x) = (x + 4)(2x - 1)
\]
3. **Expanding:**
\[
A(x) = x(2x) + x(-1) + 4(2x) + 4(-1) = 2x^2 - x + 8x - 4 = 2x^2 + 7x - 4
\]
So, the function that represents the area of the rectangular garden is:
\[
(f \cdot g)(x) = 2x^2 + 7x - 4
\]
4. **Finding the domain:**
Since the length \( f(x) = x + 4 \) must be greater than zero for the garden to have a physical meaning (length cannot be negative), we solve:
\[
x + 4 > 0 \implies x > -4
\]
The width \( g(x) = 2x - 1 \) similarly must be positive:
\[
2x - 1 > 0 \implies 2x > 1 \implies x > \frac{1}{2}
\]
The more restrictive condition is \( x > \frac{1}{2} \).
Thus, we can determine that the area function \( (f \cdot g)(x) = 2x^2 + 7x - 4 \) has the domain:
\[
\text{Domain: } x > \frac{1}{2}
\]
So, the complete result is:
\[
(f \cdot g)(x) = 2x^2 + 7x - 4 \quad \text{and the domain of } (f \cdot g)(x) \text{ is } x > \frac{1}{2}.
\]
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