To solve for \( z \) based on the information provided:
We have:
- Year 1: \( z \) wolves
- Year 2: \( 7 + z \) wolves
- Year 3: \( 3z - 3 \) wolves
We are given that the number of wolves in Year 2 is equal to the number of wolves in Year 3: \[ 7 + z = 3z - 3 \]
Now, let's solve this equation.
First, we can isolate \( z \): \[ 7 + z + 3 = 3z \] \[ 10 + z = 3z \] Subtract \( z \) from both sides: \[ 10 = 3z - z \] \[ 10 = 2z \] Now, divide both sides by 2: \[ z = 5 \]
Thus, the value of \( z \) is \( 5 \).
Next, we move on to write an expression for the number of wolves in Year 4. The expression is given as \( (x + a)(x - b) \), where \( a \) and \( b \) are whole numbers greater than 1 and less than 10.
Choosing values for \( a \) and \( b \), we could use \( a = 3 \) and \( b = 4 \) as an example. Thus, the expression becomes: \[ (x + 3)(x - 4) \]
Now, let's multiply the two terms of the expression: \[ (x + 3)(x - 4) = x^2 - 4x + 3x - 12 \] Combining like terms: \[ x^2 - x - 12 \]
So, the final expression Jin could use to describe the number of wolves in Year 4 of the study is: \[ x^2 - x - 12 \]