To determine the quadrant where \( \theta \) lies given that \( \cos \theta = -12 \) and \( \tan \theta < 0 \), we first need to address the value of \( \cos \theta \).
The cosine function has a range of values between -1 and 1, which means \( \cos \theta = -12 \) is not possible. Therefore, there is no quadrant where \( \theta \) can satisfy this condition.
Since \( \cos \theta = -12 \) is outside the valid range for the cosine function, the question does not pertain to a specific quadrant.
If we ignore the impossibility of \( \cos \theta \) being -12 and just analyze \( \tan \theta < 0 \), we can state the following for the tangent function:
- \( \tan \theta \) is positive in Quadrants I and III.
- \( \tan \theta \) is negative in Quadrants II and IV.
However, since the value of \( \cos \theta = -12 \) negates the validity of Quadrants, the answer cannot be determined under standard trigonometric conditions.
Therefore, the correct response is that the scenario is not possible.