To find \((f + g)(x)\), we need to add the functions \(f(x)\) and \(g(x)\).
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Identify the functions:
- \(f(x) = -2x^2 + 4x - 7\)
- \(g(x) = -\sqrt[3]{x - 1} + 2\)
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Add the functions: \[ (f + g)(x) = f(x) + g(x) = (-2x^2 + 4x - 7) + (-\sqrt[3]{x - 1} + 2) \] Simplifying this: \[ (f + g)(x) = -2x^2 + 4x - 7 - \sqrt[3]{x - 1} + 2 \] \[ (f + g)(x) = -2x^2 + 4x - 5 - \sqrt[3]{x - 1} \]
So, \[ (f + g)(x) = -2x^2 + 4x - 5 - \sqrt[3]{x - 1} \]
- Determine the domain of \((f + g)(x)\):
- The function \(f(x)\) is a polynomial, which is defined for all \(x\).
- The function \(g(x) = -\sqrt[3]{x - 1} + 2\) is also defined for all \(x\) since the cube root function is defined for all real numbers.
Thus, the domain of \((f + g)(x)\) is: \[ (-\infty, \infty) \]
Conclusion:
- \((f + g)(x) = -2x^2 + 4x - 5 - \sqrt[3]{x - 1}\)
- The domain of \((f + g)(x)\) is \((- \infty, \infty)\)