To find \((f + g + h)(x)\), we need to combine the given functions \(f(x)\), \(g(x)\), and \(h(x)\).
-
Given:
- \(f(x) = \sqrt{x - 5} + 2\)
- \(g(x) = -2\sqrt{x - 5} - 7\)
- \(h(x) = -\sqrt{x - 5}\)
-
Let's compute \((f + g + h)(x)\):
\[ (f + g + h)(x) = f(x) + g(x) + h(x) \]
Plugging in the expressions:
\[ (f + g + h)(x) = \left(\sqrt{x - 5} + 2\right) + \left(-2\sqrt{x - 5} - 7\right) + \left(-\sqrt{x - 5}\right) \]
Combining like terms:
\[ = \sqrt{x - 5} - 2\sqrt{x - 5} - \sqrt{x - 5} + 2 - 7 \] \[ = (1 - 2 - 1)\sqrt{x - 5} + (2 - 7) \] \[ = -2\sqrt{x - 5} - 5 \]
Therefore, we have:
\[ (f + g + h)(x) = -2\sqrt{x - 5} - 5 \]
-
Next, we need to determine the domain of \((f + g + h)(x)\). The domain of the combined function is influenced by the domain of each individual function.
- For \(f(x)\), \(\sqrt{x - 5}\) requires \(x - 5 \geq 0 \Rightarrow x \geq 5\).
- For \(g(x)\), \(-2\sqrt{x - 5}\) also requires \(x - 5 \geq 0 \Rightarrow x \geq 5\).
- For \(h(x)\), \(-\sqrt{x - 5}\) requires \(x - 5 \geq 0 \Rightarrow x \geq 5\).
Therefore, the domain of \((f + g + h)(x)\) is \(x \geq 5\).
Putting this all together, we find:
\[ (f + g + h)(x) = -2\sqrt{x - 5} - 5 \] and the domain is \(x \geq 5\).
Final answer:
- \((f+g+h)(x) = -2\sqrt{x-5} - 5\)
- The domain is \(x \geq 5\).