To find the x-intercepts of the quadratic function \(y = x^2 + 3x + 8\), we need to determine when \(y = 0\): \[ x^2 + 3x + 8 = 0 \] We can use the quadratic formula: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \] where \(a = 1\), \(b = 3\), and \(c = 8\).
- Calculate the discriminant: \[ b^2 - 4ac = 3^2 - 4 \cdot 1 \cdot 8 = 9 - 32 = -23 \]
Since the discriminant is negative (\(-23\)), this means the quadratic has no real roots. Therefore, there are no x-intercepts.
So, the correct response is: There is no x-intercept.