To find the vertex of the quadratic function \( h = 6t^2 - 24t + 30 \), we can use the formula for the vertex of a quadratic equation in the form \( ax^2 + bx + c \). The vertex occurs at \( t = -\frac{b}{2a} \).
Here, \( a = 6 \) and \( b = -24 \).
Calculating the vertex:
\[ t = -\frac{-24}{2 \times 6} = \frac{24}{12} = 2 \]
Now, we can find the corresponding height \( h \) at \( t = 2 \):
\[ h = 6(2)^2 - 24(2) + 30 \] \[ h = 6(4) - 48 + 30 \] \[ h = 24 - 48 + 30 \] \[ h = 6 \]
Thus, the vertex of the function is \( (2, 6) \).
The correct interpretation of the vertex is (2, 6), indicating that at \( t = 2 \) seconds, the height of the owl is 6 feet.