To find the vertex of the quadratic function given by the equation \( h(t) = -6t^2 - 24t + 20 \), we can use the vertex formula for a quadratic function in the standard form \( h(t) = at^2 + bt + c \). The vertex \( t \)-coordinate can be found using the formula:
\[ t = -\frac{b}{2a} \]
In this equation:
- \( a = -6 \)
- \( b = -24 \)
Now, substituting these values into the vertex formula:
\[ t = -\frac{-24}{2 \cdot -6} = \frac{24}{-12} = -2 \]
Next, to find the corresponding \( h \)-coordinate of the vertex, substitute \( t = -2 \) back into the original function:
\[ h(-2) = -6(-2)^2 - 24(-2) + 20 \] \[ = -6(4) + 48 + 20 \] \[ = -24 + 48 + 20 \] \[ = 44 \]
Thus, the vertex of the function is at the point \( (-2, 44) \).
Therefore, the ordered pair that represents the vertex is:
\[ \boxed{(-2, 44)} \]