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Complete the tables to show the parent function y=f(x) and its translation y=f(x+5) . (2 points) Original Function x y=f(x) −2...Question
Complete the tables to show the parent function y =f(x) and its translation y =f(x +5).
Original Function
x y=f(x)
-2 5
-1 2
0 1
1 2
2 5
Translated Function
x y =f(x +5)
5
2
1
2
5
Original Function
x y=f(x)
-2 5
-1 2
0 1
1 2
2 5
Translated Function
x y =f(x +5)
5
2
1
2
5
Answers
GPT-4o mini
To complete the tables for the parent function \( y = f(x) \) and its translation \( y = f(x + 5) \), we need to understand that the translation \( f(x + 5) \) shifts the graph of the function \( f(x) \) to the left by 5 units. This means that each \( x \) value in the original function will be decreased by 5 in the translated function.
### Original Function
The original function values are provided as follows:
| x | y = f(x) |
|----|----------|
| -2 | 5 |
| -1 | 2 |
| 0 | 1 |
| 1 | 2 |
| 2 | 5 |
### Translated Function
To find the translated function \( y = f(x + 5) \), we will evaluate \( f \) at \( x \) values that are 5 units less than those in the original function table:
1. For \( x = -5 \), \( y = f(-5) = f(-2) = 5 \).
2. For \( x = -4 \), \( y = f(-4) = f(-1) = 2 \).
3. For \( x = -5 \), \( y = f(-5) = f(0) = 1 \).
4. For \( x = -3 \), \( y = f(-3) = f(1) = 2 \).
5. For \( x = -2 \), \( y = f(-2) = f(2) = 5 \).
The completed tables will look like this:
### Translated Function Table
| x | y = f(x + 5) |
|----|--------------|
| -5 | 5 |
| -4 | 2 |
| -3 | 1 |
| -2 | 2 |
| -1 | 5 |
So, the completed function tables are:
### Original Function
| x | y = f(x) |
|----|----------|
| -2 | 5 |
| -1 | 2 |
| 0 | 1 |
| 1 | 2 |
| 2 | 5 |
### Translated Function
| x | y = f(x + 5) |
|----|--------------|
| -5 | 5 |
| -4 | 2 |
| -3 | 1 |
| -2 | 2 |
| -1 | 5 |
### Original Function
The original function values are provided as follows:
| x | y = f(x) |
|----|----------|
| -2 | 5 |
| -1 | 2 |
| 0 | 1 |
| 1 | 2 |
| 2 | 5 |
### Translated Function
To find the translated function \( y = f(x + 5) \), we will evaluate \( f \) at \( x \) values that are 5 units less than those in the original function table:
1. For \( x = -5 \), \( y = f(-5) = f(-2) = 5 \).
2. For \( x = -4 \), \( y = f(-4) = f(-1) = 2 \).
3. For \( x = -5 \), \( y = f(-5) = f(0) = 1 \).
4. For \( x = -3 \), \( y = f(-3) = f(1) = 2 \).
5. For \( x = -2 \), \( y = f(-2) = f(2) = 5 \).
The completed tables will look like this:
### Translated Function Table
| x | y = f(x + 5) |
|----|--------------|
| -5 | 5 |
| -4 | 2 |
| -3 | 1 |
| -2 | 2 |
| -1 | 5 |
So, the completed function tables are:
### Original Function
| x | y = f(x) |
|----|----------|
| -2 | 5 |
| -1 | 2 |
| 0 | 1 |
| 1 | 2 |
| 2 | 5 |
### Translated Function
| x | y = f(x + 5) |
|----|--------------|
| -5 | 5 |
| -4 | 2 |
| -3 | 1 |
| -2 | 2 |
| -1 | 5 |