To determine how many times larger \( 9 \times 10^{-8} \) is than \( 3 \times 10^{-12} \), you can divide the two numbers:
\[ \frac{9 \times 10^{-8}}{3 \times 10^{-12}} \]
First, divide the coefficients (9 and 3):
\[ \frac{9}{3} = 3 \]
Next, divide the powers of ten. When dividing, you subtract the exponents:
\[ 10^{-8} \div 10^{-12} = 10^{-8 - (-12)} = 10^{-8 + 12} = 10^{4} \]
Now, combine the results:
\[ 3 \times 10^{4} \]
Thus, \( 9 \times 10^{-8} \) is \( 3 \times 10^4 \) times larger than \( 3 \times 10^{-12} \).
The correct answer is:
3×10⁴