Question
If someone feeds their cat 4/5 cup of food a day, and they feed the cat 1/2 cup of the food in the evening how much food does the person give th cat the rest of the day
Answers
GPT-4o mini
To find out how much food the person gives the cat for the rest of the day, you first need to determine how much food has been fed in the evening and then subtract that from the total daily amount of food.
1. Total daily amount of food: \( \frac{4}{5} \) cup
2. Amount fed in the evening: \( \frac{1}{2} \) cup
Now, let's convert \( \frac{1}{2} \) cup to a fraction with a denominator of 5 to make it easier to subtract:
\[
\frac{1}{2} = \frac{5}{10} = \frac{2.5}{5} (when converted)
\]
Next, let's rewrite \( \frac{4}{5} \) and \( \frac{1}{2} \) with a common denominator (5):
\[
\frac{1}{2} = \frac{2.5}{5} or \frac{10}{10}
\]
The actual calculations to subtract:
\[
\text{Food given during the day} = \left(\frac{4}{5} - \frac{2.5}{5}\right) \text{ or } \left(\frac{4}{5} - \frac{1}{2}\right) = \frac{4 - 2.5}{5} = \frac{1.5}{5}
\]
Now, performing the calculations directly:
- \( \frac{4}{5} \) cup minus \( \frac{1/2} = \frac{2.5}{5}\) cup can be evaluated to get:
\[
= \frac{4}{5} - \frac{2.5}{5} = \frac{4 - 2.5}{5} = \frac{1.5}{5} = \frac{3}{10} cup.
\]
Thus, the amount of food given to the cat for the rest of the day before evening feeding is \( \frac{3}{10} \) cup.
1. Total daily amount of food: \( \frac{4}{5} \) cup
2. Amount fed in the evening: \( \frac{1}{2} \) cup
Now, let's convert \( \frac{1}{2} \) cup to a fraction with a denominator of 5 to make it easier to subtract:
\[
\frac{1}{2} = \frac{5}{10} = \frac{2.5}{5} (when converted)
\]
Next, let's rewrite \( \frac{4}{5} \) and \( \frac{1}{2} \) with a common denominator (5):
\[
\frac{1}{2} = \frac{2.5}{5} or \frac{10}{10}
\]
The actual calculations to subtract:
\[
\text{Food given during the day} = \left(\frac{4}{5} - \frac{2.5}{5}\right) \text{ or } \left(\frac{4}{5} - \frac{1}{2}\right) = \frac{4 - 2.5}{5} = \frac{1.5}{5}
\]
Now, performing the calculations directly:
- \( \frac{4}{5} \) cup minus \( \frac{1/2} = \frac{2.5}{5}\) cup can be evaluated to get:
\[
= \frac{4}{5} - \frac{2.5}{5} = \frac{4 - 2.5}{5} = \frac{1.5}{5} = \frac{3}{10} cup.
\]
Thus, the amount of food given to the cat for the rest of the day before evening feeding is \( \frac{3}{10} \) cup.