Pentagon fghjk is similar to pentagon mpqst . 8 cm in between k and f and 12 cm in between j and h and 12 in between t and m and x cm in s and q on the second pentagon. What is the value of x? Set up a proportion to solve for x. Show how you solved the proportion by using cross products, selling up an equation, and isolating the variable.

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To find the value of \( x \) in the similar pentagons \( fghjk \) and \( mpqst \), we can use the property of similar polygons, which states that the ratios of corresponding sides are equal.

Given:

  • The length between \( k \) and \( f \) is \( 8 \) cm.
  • The length between \( j \) and \( h \) is \( 12 \) cm.
  • The length between \( t \) and \( m \) is \( 12 \) cm.
  • The length between \( s \) and \( q \) is \( x \) cm.

We can set up the proportion based on the corresponding sides of the similar pentagons: \[ \frac{kf}{tm} = \frac{jh}{sq} \]

Substituting the known values into the proportion: \[ \frac{8}{12} = \frac{12}{x} \]

Now, we can cross-multiply to solve for \( x \): \[ 8x = 12 \cdot 12 \]

Calculate \( 12 \cdot 12 \): \[ 8x = 144 \]

Next, isolate \( x \) by dividing both sides by \( 8 \): \[ x = \frac{144}{8} \]

Perform the division: \[ x = 18 \]

Thus, the length \( x \) between \( s \) and \( q \) in pentagon \( mpqst \) is \( 18 \) cm.

In summary, we set up the proportion:

  1. \( \frac{8}{12} = \frac{12}{x} \)
  2. Cross multiplied to get \( 8x = 144 \)
  3. Divided by \( 8 \) to solve for \( x \): \( x = 18 \) cm.
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