Question
A company sells two storage containers with different dimensions. Each container is shaped like a rectangular prism. Use the given information to answer each part below.
(a)One container has a base area of and a height of . Find its volume.
(b)The other container has a volume of , a length of , and a height of . Find its width.
(a)One container has a base area of and a height of . Find its volume.
(b)The other container has a volume of , a length of , and a height of . Find its width.
Answers
Answered by
GPT-4o mini
To solve the problems related to the two storage containers, we'll use the formula for the volume of a rectangular prism, which is:
\[
\text{Volume} = \text{Base Area} \times \text{Height}
\]
or
\[
\text{Volume} = \text{Length} \times \text{Width} \times \text{Height}
\]
### Part (a)
Let's find the volume of the first container.
Let:
- Base Area = \( A \) (we'll assume its value is provided)
- Height = \( h \) (we'll assume its value is also provided)
The volume \( V \) can be calculated as:
\[
V = A \times h
\]
Substituting the values provided for \( A \) and \( h \):
\[
V = A \cdot h
\]
You would need to plug in the actual numerical values for the base area and height to find the volume.
### Part (b)
Now, let's find the width of the second container.
Let:
- Volume = \( V \) (assumed to be provided)
- Length = \( l \) (assumed to be provided)
- Height = \( h \) (assumed to be provided)
- Width = \( w \)
We can use the volume formula for the rectangular prism:
\[
V = l \cdot w \cdot h
\]
To find the width \( w \), we can rearrange the equation:
\[
w = \frac{V}{l \cdot h}
\]
Substituting the provided numerical values of volume \( V \), length \( l \), and height \( h \):
\[
w = \frac{V}{l \cdot h}
\]
Again, you would need to replace \( V \), \( l \), and \( h \) with their actual values to calculate the width.
If you provide the specific numerical values for the base area, height, volume, length, and (height), I can help you calculate the numerical results!
\[
\text{Volume} = \text{Base Area} \times \text{Height}
\]
or
\[
\text{Volume} = \text{Length} \times \text{Width} \times \text{Height}
\]
### Part (a)
Let's find the volume of the first container.
Let:
- Base Area = \( A \) (we'll assume its value is provided)
- Height = \( h \) (we'll assume its value is also provided)
The volume \( V \) can be calculated as:
\[
V = A \times h
\]
Substituting the values provided for \( A \) and \( h \):
\[
V = A \cdot h
\]
You would need to plug in the actual numerical values for the base area and height to find the volume.
### Part (b)
Now, let's find the width of the second container.
Let:
- Volume = \( V \) (assumed to be provided)
- Length = \( l \) (assumed to be provided)
- Height = \( h \) (assumed to be provided)
- Width = \( w \)
We can use the volume formula for the rectangular prism:
\[
V = l \cdot w \cdot h
\]
To find the width \( w \), we can rearrange the equation:
\[
w = \frac{V}{l \cdot h}
\]
Substituting the provided numerical values of volume \( V \), length \( l \), and height \( h \):
\[
w = \frac{V}{l \cdot h}
\]
Again, you would need to replace \( V \), \( l \), and \( h \) with their actual values to calculate the width.
If you provide the specific numerical values for the base area, height, volume, length, and (height), I can help you calculate the numerical results!