To find the efficiency of energy transfer between the harbor seal and the polar bear using the formula provided, we can plug in the values as follows:
- Energy level transferred to the next level (polar bear): 375 Kcal (energy received by the polar bear)
- Total energy input (harbor seal): 2,500 Kcal (energy source before transfer)
Now, applying the formula:
\[ \text{Efficiency} = \left( \frac{\text{Energy level transferred}}{\text{Total energy input}} \right) \times 100 \]
Substituting in the numbers:
\[ \text{Efficiency} = \left( \frac{375 \text{ Kcal}}{2500 \text{ Kcal}} \right) \times 100 \]
Calculating the fraction:
\[ \frac{375}{2500} = 0.15 \]
Now, multiply by 100 to get the efficiency percentage:
\[ 0.15 \times 100 = 15% \]
Thus, the efficiency of energy transfer between the harbor seal and the polar bear is 15%.
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