Question

Use the following formula to find the efficiency of energy transfer between the harbor seal (2,500 Kcal) and a polar bear (375 Kcal). (Energy level transfered to next level)(Total energy input) × 100 (1 point) Responses 12% 12% 15% 15% 10% 10% 20%

Answer 1

To find the efficiency of energy transfer between the harbor seal and the polar bear using the formula provided, we can plug in the values as follows:

1. **Energy level transferred to the next level (polar bear):** 375 Kcal (energy received by the polar bear)
2. **Total energy input (harbor seal):** 2,500 Kcal (energy source before transfer)

Now, applying the formula:

\[
\text{Efficiency} = \left( \frac{\text{Energy level transferred}}{\text{Total energy input}} \right) \times 100
\]

Substituting in the numbers:

\[
\text{Efficiency} = \left( \frac{375 \text{ Kcal}}{2500 \text{ Kcal}} \right) \times 100
\]

Calculating the fraction:

\[
\frac{375}{2500} = 0.15
\]

Now, multiply by 100 to get the efficiency percentage:

\[
0.15 \times 100 = 15\%
\]

Thus, the efficiency of energy transfer between the harbor seal and the polar bear is **15%**.