Use the following formula to find the efficiency of energy transfer between the harbor seal (2,500 Kcal) and a polar bear (375 Kcal). (Energy level transfered to next level)(Total energy input) × 100 (1 point) Responses 12% 12% 15% 15% 10% 10% 20%

Answer 1

To find the efficiency of energy transfer between the harbor seal and the polar bear using the formula provided, we can plug in the values as follows:

1. Energy level transferred to the next level (polar bear): 375 Kcal (energy received by the polar bear)
2. Total energy input (harbor seal): 2,500 Kcal (energy source before transfer)

Now, applying the formula:

$$\text{Efficiency}=\left(\frac{\text{Energy level transferred}}{\text{Total energy input}}\right)\times 100$$

Substituting in the numbers:

$$\text{Efficiency}=\left(\frac{375\text{ Kcal}}{2500\text{ Kcal}}\right)\times 100$$

Calculating the fraction:

$$\frac{375}{2500}=0.15$$

Now, multiply by 100 to get the efficiency percentage:

$$0.15\times 100=15$$

Thus, the efficiency of energy transfer between the harbor seal and the polar bear is 15%.