Question

The measures of the angles of a triangle are 50°, 35°, and 95°. What is the measure of the largest exterior angle of the triangle?




85º


130º


145º


150º

Answer 1

To find the largest exterior angle of the triangle with interior angles of 50°, 35°, and 95°, we first need to recall that the exterior angle is equal to 180° minus the corresponding interior angle.

Let's calculate the exterior angles for each of the interior angles:

1. For the interior angle of 50°:
\[
\text{Exterior angle} = 180° - 50° = 130°
\]

2. For the interior angle of 35°:
\[
\text{Exterior angle} = 180° - 35° = 145°
\]

3. For the interior angle of 95°:
\[
\text{Exterior angle} = 180° - 95° = 85°
\]

Now, we have the exterior angles as:
- 130° (for 50°)
- 145° (for 35°)
- 85° (for 95°)

The largest exterior angle among these is:
\[
145°
\]

Therefore, the measure of the largest exterior angle of the triangle is **145°**.