Question

Use the equation to answer the question.

H2SO4+HI→H2S+I2+H2O


Which option shows a correctly balanced chemical equation?

(1 point)
Responses

H2SO4+8HI→H2S+8I2+4H2O
h sub 2 S O sub 4 plus 8H I rightarrow h sub 2 s plus 8i sub 2 plus 4h sub 2 o

H2SO4+HI→H2S+I2+H2O
h sub 2 S O sub 4 plus H I rightarrow h sub 2 s plus i sub 2 plus h sub 2 o

2H2SO4+2HI→2H2S+I2+4H2O
2 h sub 2 S O sub 4 plus 2H I rightarrow 2 h sub 2 s plus i sub 2 plus 4h sub 2 o

H2SO4+8HI→H2S+4I2+4H2O

Answer 1

To determine the correctly balanced chemical equation for the reaction \( \text{H}_2\text{SO}_4 + \text{HI} \rightarrow \text{H}_2\text{S} + \text{I}_2 + \text{H}_2\text{O} \), we need to balance the atoms of each element on both sides of the equation.

1. Count the number of each type of atom on both sides.
2. Ensure that they are equal on both the reactant and product sides.

Let's examine the provided options:

1. **H2SO4 + 8HI → H2S + 8I2 + 4H2O**
- Reactants: 1 S, 4 O, 2 H (from H2SO4) + 8 H, 8 I (from HI) → total: 2 H + 8 H = 10 H, 1 S, 8 I, 4 O
- Products: 2 H (from H2S) + 4 H (from H2O) = 6 H, 1 S, 8 I (from 8I2), 4 O
- Not balanced.

2. **H2SO4 + HI → H2S + I2 + H2O**
- Reactants: 1 S, 4 O, 2 H (from H2SO4) + 1 H, 1 I (from HI) → total: 2 H + 1 H = 3 H, 1 S, 1 I, 4 O
- Products: 2 H (from H2S) + 2 H (from H2O) = 4 H, 1 S, 2 I, 1 O
- Not balanced.

3. **2 H2SO4 + 2 HI → 2 H2S + I2 + 4 H2O**
- Reactants: 2 S, 8 O, 4 H (from 2 H2SO4) + 2 H, 2 I (from 2 HI) → total: 4 H + 2 H = 6 H, 2 S, 2 I, 8 O
- Products: 4 H (from 2 H2S) + 8 H (from 4 H2O) = 12 H, 2 S, 2 I (from 2I2), 4 O
- Not balanced.

4. **H2SO4 + 8HI → H2S + 4I2 + 4H2O**
- Reactants: 1 S, 4 O, 2 H (from H2SO4) + 8 H, 8 I (from HI) → total: 2 H + 8 H = 10 H, 1 S, 8 I, 4 O
- Products: 2 H (from H2S) + 8 H (from 4 H2O) + 8 I (from 4I2) → total: 6 H, 2 I; Not balanced.

After analyzing the options, it appears that none of the equations are correctly balanced.

To actually balance the equation:

1. Start with the unbalanced equation:
\[ \text{H}_2\text{SO}_4 + \text{HI} \rightarrow \text{H}_2\text{S} + \text{I}_2 + \text{H}_2\text{O} \]

2. Balance the iodine by ensuring that 2 iodine are produced from 4 HI reactants:
\[ \text{H}_2\text{SO}_4 + 4 \text{HI} \rightarrow \text{H}_2\text{S} + 2 \text{I}_2 + 2 \text{H}_2\text{O} \]

Thus, the balanced equation is:
\[ \text{H}_2\text{SO}_4 + 4 \text{HI} \rightarrow \text{H}_2\text{S} + 2 \text{I}_2 + 2 \text{H}_2\text{O} \]

It seems all presented options do not represent a correctly balanced chemical equation. Please double-check if there are any additional options for a final choice.