To determine what fraction of the students are athletes that also play in the fall, we can follow these steps:
- Let the total number of students be represented by 1 (this is our whole).
- The fraction of students that are athletes is given as \( \frac{1}{6} \).
- Among the athletes, \( \frac{5}{7} \) participate in the fall.
Now, to find the fraction of the total students that are athletes playing in the fall, we multiply these two fractions:
\[ \text{Fraction of students who are athletes playing in the fall} = \left(\frac{1}{6}\right) \times \left(\frac{5}{7}\right) \]
Calculating this gives:
\[ \frac{1}{6} \times \frac{5}{7} = \frac{1 \times 5}{6 \times 7} = \frac{5}{42} \]
Thus, the fraction of the students who are athletes that also play in the fall is \( \frac{5}{42} \).
So, the final answer is:
\(\frac{5}{42}\) are athletes that also play in the fall.