To find the image of quadrilateral ABCD after a dilation by a scale factor of 2 centered at the origin, we need to multiply the coordinates of each vertex by the scale factor (2).
The original vertices are:
- A(-4, 2)
- B(0, 6)
- C(4, 6)
- D(8, 2)
Let's calculate the coordinates after dilation:
-
For A(-4, 2):
- A' = (-4 * 2, 2 * 2) = (-8, 4)
-
For B(0, 6):
- B' = (0 * 2, 6 * 2) = (0, 12)
-
For C(4, 6):
- C' = (4 * 2, 6 * 2) = (8, 12)
-
For D(8, 2):
- D' = (8 * 2, 2 * 2) = (16, 4)
So, the coordinates of the dilated quadrilateral A'B'C'D' are:
- A'(-8, 4)
- B'(0, 12)
- C'(8, 12)
- D'(16, 4)
Now, let's compare these coordinates with the options given:
- A' at (-8, 4), B' at (-2, 8), C' at (2, 8), D' at (6, 4).
- A' at (-8, 4), B' at (0, 12), C' at (8, 12), D' at (16, 4).
- A' at (-8, 2), B' at (-2, 6), C' at (2, 6), D' at (6, 2).
- A' at (-2, 1), B' at (0, 3), C' at (2, 3), D' at (4, 1).
The correct response is:
2. Quadrilateral A'B'C'D' is on a coordinate plane. A' at (-8, 4), B' at (0, 12), C' at (8, 12), and D' at (16, 4).