Question
A veterinarian would like a heat pack developed to strap to the paw of a cat or small dog. The normal body temperature of a cat or small dog is just a few degrees higher than that of humans. The veterinarian wants to design the heat pack to contain 50 grams of water and reach a temperature of 46°C. The heat pack should be designed to have the same concentration as the solution in the passage that reaches 46°C. How much calcium chloride should be added to the heat pack?
A.
2 grams
B.
6 grams
C.
12 grams
D.
24 grams
A.
2 grams
B.
6 grams
C.
12 grams
D.
24 grams
Answers
GPT-4o mini
To determine how much calcium chloride (CaCl₂) should be added to the heat pack containing 50 grams of water to reach a temperature of 46°C, we need to consider the colligative properties of the solution, specifically freezing point depression or boiling point elevation. However, we don't have information about the initial temperature of the water or the freezing point depression data.
The passage you referred to mentions a previous solution concentration, but without specific details about the properties or the context of that solution, we cannot directly calculate the amount of calcium chloride needed based on concentration.
Assuming the problem might expect that we understand the general behavior of a calcium chloride solution in water, we know that calcium chloride dissociates into three ions (one Ca²⁺ and two Cl⁻) when dissolved in water, affecting the temperature based on its molality.
A common study or experimental design could use trial and error to find the amount of calcium chloride needed to achieve the desired temperature, if it reached 46 degrees based on empirical testing.
Assuming the answer options are derived from known values or experimental data, without specific temperature data or a formula given, I'd estimate that the right choice typically is based on common knowledge of similar solutions.
With that in mind, based on similar contexts where calcium chloride is used, often smaller amounts provide significant heating (around 5-20 grams typically), the answer would most logically lean towards the higher amounts.
**Answer: D. 24 grams**
This selection balances the idea that a higher concentration often would result in elevated temperature, keeping in mind the context of small animals which may require effective but safe heating solutions.
The passage you referred to mentions a previous solution concentration, but without specific details about the properties or the context of that solution, we cannot directly calculate the amount of calcium chloride needed based on concentration.
Assuming the problem might expect that we understand the general behavior of a calcium chloride solution in water, we know that calcium chloride dissociates into three ions (one Ca²⁺ and two Cl⁻) when dissolved in water, affecting the temperature based on its molality.
A common study or experimental design could use trial and error to find the amount of calcium chloride needed to achieve the desired temperature, if it reached 46 degrees based on empirical testing.
Assuming the answer options are derived from known values or experimental data, without specific temperature data or a formula given, I'd estimate that the right choice typically is based on common knowledge of similar solutions.
With that in mind, based on similar contexts where calcium chloride is used, often smaller amounts provide significant heating (around 5-20 grams typically), the answer would most logically lean towards the higher amounts.
**Answer: D. 24 grams**
This selection balances the idea that a higher concentration often would result in elevated temperature, keeping in mind the context of small animals which may require effective but safe heating solutions.