Question
A community swimming pool starts with 250 gallons of water. Julian starts filling the pool at a rate of 500 gallons per hour.
Keep going. What is the number of gallons of water in the pool after 1, 2, and 3 hours?
Time in hours Gallons of water in the pool
0 250
1
2
3
Keep going. What is the number of gallons of water in the pool after 1, 2, and 3 hours?
Time in hours Gallons of water in the pool
0 250
1
2
3
Answers
GPT-4o mini
To calculate the number of gallons of water in the pool after 1, 2, and 3 hours, we can use the formula:
\[
\text{Gallons of water} = \text{Initial gallons} + (\text{Filling rate} \times \text{Time})
\]
Given that the initial amount of water is 250 gallons and Julian fills the pool at a rate of 500 gallons per hour, we can calculate the values for each hour:
### After 1 hour:
\[
\text{Gallons} = 250 + (500 \times 1) = 250 + 500 = 750
\]
### After 2 hours:
\[
\text{Gallons} = 250 + (500 \times 2) = 250 + 1000 = 1250
\]
### After 3 hours:
\[
\text{Gallons} = 250 + (500 \times 3) = 250 + 1500 = 1750
\]
Now we can summarize the results in a table:
| Time in hours | Gallons of water in the pool |
|---------------|-------------------------------|
| 0 | 250 |
| 1 | 750 |
| 2 | 1250 |
| 3 | 1750 |
\[
\text{Gallons of water} = \text{Initial gallons} + (\text{Filling rate} \times \text{Time})
\]
Given that the initial amount of water is 250 gallons and Julian fills the pool at a rate of 500 gallons per hour, we can calculate the values for each hour:
### After 1 hour:
\[
\text{Gallons} = 250 + (500 \times 1) = 250 + 500 = 750
\]
### After 2 hours:
\[
\text{Gallons} = 250 + (500 \times 2) = 250 + 1000 = 1250
\]
### After 3 hours:
\[
\text{Gallons} = 250 + (500 \times 3) = 250 + 1500 = 1750
\]
Now we can summarize the results in a table:
| Time in hours | Gallons of water in the pool |
|---------------|-------------------------------|
| 0 | 250 |
| 1 | 750 |
| 2 | 1250 |
| 3 | 1750 |
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