How many times larger is 9 × 10^−8

Question

than 3 × 10^−12
?

Answer 1

To determine how many times larger \( 9 \times 10^{-8} \) is than \( 3 \times 10^{-12} \), we can divide the two quantities:

\[ \frac{9 \times 10^{-8}}{3 \times 10^{-12}} \]

First, we'll divide the coefficients:

\[ \frac{9}{3} = 3 \]

Next, we'll divide the powers of ten. When dividing powers, we subtract the exponents:

\[ 10^{-8} \div 10^{-12} = 10^{-8 - (-12)} = 10^{-8 + 12} = 10^4 \]

Combining both results, we have:

\[ 3 \times 10^4 \]

Thus, \( 9 \times 10^{-8} \) is \( 3 \times 10^4 \) times larger than \( 3 \times 10^{-12} \).

Calculating \( 3 \times 10^4 \):

\[ 3 \times 10^4 = 3 \times 10000 = 30000 \]

Therefore, \( 9 \times 10^{-8} \) is 30,000 times larger than \( 3 \times 10^{-12} \).