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Factor out the greatest common factor from the following polynomial: 28a^7b^7-20ab+16a^4b
Write an expression for the length of the rectangle. (Hint; Factor the area binomial and recall that Area= width • length). Area is 8x^5-32x^2 and the width is 8x^2
Write an expression for the length of the rectangle. (Hint; Factor the area binomial and recall that Area= width • length). Area is 8x^5-32x^2 and the width is 8x^2
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Answered by
GPT-4o mini
To factor out the greatest common factor (GCF) from the polynomial \( 28a^7b^7 - 20ab + 16a^4b \):
1. Identify the coefficients: 28, -20, and 16. The GCF of these numbers is 4.
2. Identify the variables:
- For \( a \), the smallest exponent is 1 (in \( -20ab \)), so we can factor out \( a^1 \).
- For \( b \), the smallest exponent is 1 (also in \( -20ab \)), so we can factor out \( b^1 \).
3. Thus, the GCF is \( 4ab \).
Now factor this GCF out:
\[
28a^7b^7 - 20ab + 16a^4b = 4ab(7a^6b^6 - 5 + 4a^3)
\]
So the factored expression is:
\[
4ab(7a^6b^6 + 4a^3 - 5)
\]
---
Next, to find the length of the rectangle given the area \( 8x^5 - 32x^2 \) and the width \( 8x^2 \):
1. Factor the area first:
\[
8x^5 - 32x^2 = 8x^2(x^3 - 4)
\]
2. We know:
\[
\text{Area} = \text{Width} \times \text{Length}
\]
Thus:
\[
8x^5 - 32x^2 = 8x^2 \times \text{Length}
\]
3. Now set up the equation:
\[
8x^2(x^3 - 4) = 8x^2 \times \text{Length}
\]
4. Divide both sides by \( 8x^2 \):
\[
x^3 - 4 = \text{Length}
\]
So, the expression for the length of the rectangle is:
\[
\text{Length} = x^3 - 4
\]
1. Identify the coefficients: 28, -20, and 16. The GCF of these numbers is 4.
2. Identify the variables:
- For \( a \), the smallest exponent is 1 (in \( -20ab \)), so we can factor out \( a^1 \).
- For \( b \), the smallest exponent is 1 (also in \( -20ab \)), so we can factor out \( b^1 \).
3. Thus, the GCF is \( 4ab \).
Now factor this GCF out:
\[
28a^7b^7 - 20ab + 16a^4b = 4ab(7a^6b^6 - 5 + 4a^3)
\]
So the factored expression is:
\[
4ab(7a^6b^6 + 4a^3 - 5)
\]
---
Next, to find the length of the rectangle given the area \( 8x^5 - 32x^2 \) and the width \( 8x^2 \):
1. Factor the area first:
\[
8x^5 - 32x^2 = 8x^2(x^3 - 4)
\]
2. We know:
\[
\text{Area} = \text{Width} \times \text{Length}
\]
Thus:
\[
8x^5 - 32x^2 = 8x^2 \times \text{Length}
\]
3. Now set up the equation:
\[
8x^2(x^3 - 4) = 8x^2 \times \text{Length}
\]
4. Divide both sides by \( 8x^2 \):
\[
x^3 - 4 = \text{Length}
\]
So, the expression for the length of the rectangle is:
\[
\text{Length} = x^3 - 4
\]
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