Quadrilateral ABCD

is inscribed in circle O
. Given m∠A=78°
and m∠B=125°
, find m∠C, m∠D

m∠C=55°, m∠D=55°

m∠C=55°, m∠D=102°

m∠C=102°, m∠D=55°

m∠C=102°, m∠D=102°

1 answer

In a cyclic quadrilateral (a quadrilateral inscribed in a circle), the opposite angles are supplementary. This means that the sum of the measures of opposite angles equals 180 degrees.

We are given:

  • \( m∠A = 78° \)
  • \( m∠B = 125° \)

To find \( m∠C \) and \( m∠D \):

  1. Using the property of opposite angles in cyclic quadrilaterals, we know:
    • \( m∠A + m∠C = 180° \)
    • \( m∠B + m∠D = 180° \)

Now we can calculate \( m∠C \):

  • \( m∠C = 180° - m∠A = 180° - 78° = 102° \)

Next, we can calculate \( m∠D \):

  • \( m∠D = 180° - m∠B = 180° - 125° = 55° \)

Thus, we find:

  • \( m∠C = 102° \)
  • \( m∠D = 55° \)

Therefore, the correct answer is: m∠C = 102°, m∠D = 55°.