A circle is centered at (−3, 2) and has a radius of 2. Which of the following is the equation for this circle? (5 points)

(x + 3)2 + (y − 2)2 = 2

(x − 3)2 + (y + 2)2 = 4

(x + 3)2 + (y − 2)2 = 4

(x − 3)2 + (y + 2)2 = 2

1 answer

To write the equation of a circle, we use the standard formula:

\[ (x - h)^2 + (y - k)^2 = r^2 \]

where \((h, k)\) is the center of the circle and \(r\) is the radius.

In your case, the center of the circle is \((-3, 2)\), which means \(h = -3\) and \(k = 2\). The radius \(r\) is given as \(2\). Therefore, \(r^2 = 2^2 = 4\).

Plugging in the values into the formula, we have:

\[ (x - (-3))^2 + (y - 2)^2 = 4 \]

This simplifies to:

\[ (x + 3)^2 + (y - 2)^2 = 4 \]

So, the correct equation for the circle is:

\[ (x + 3)^2 + (y - 2)^2 = 4 \]

Thus, the correct option from your list is:

(x + 3)² + (y − 2)² = 4.