Table 1

Question

f (x)
-1
-12
1
-2
3
And
x
4
5
-2
6
-12

Table 2
g(x)
-1
-8
0
-5
1
And
x
-2
2
1
3
4

What is the Solution Set?

{?,?}

Answer 1

To find the solution set for the given tables, we need to identify the values of \( x \) where \( f(x) = g(x) \).

From Table 1, we have:

| \( x \) | \( f(x) \) | |---------|------------| | 4 | -1 | | 5 | -12 | | -2 | 1 | | 6 | -2 | | -12 | 3 |

From Table 2, we have:

| \( x \) | \( g(x) \) | |---------|------------| | -2 | -1 | | 2 | -8 | | 1 | 0 | | 3 | -5 | | 4 | 1 |

Now let's list the values of \( f(x) \) and \( g(x) \):

For \( f(x) \):

• \( f(4) = -1 \)
• \( f(5) = -12 \)
• \( f(-2) = 1 \)
• \( f(6) = -2 \)
• \( f(-12) = 3 \)

For \( g(x) \):

• \( g(-2) = -1 \)
• \( g(2) = -8 \)
• \( g(1) = 0 \)
• \( g(3) = -5 \)
• \( g(4) = 1 \)

Next, we will compare the values:

1. For \( x = 4 \):

   • \( f(4) = -1 \) and \( g(4) = 1 \) → not equal

2. For \( x = 5 \):

   • \( f(5) = -12 \) and doesn't exist in \( g(x) \) → not equal

3. For \( x = -2 \):

   • \( f(-2) = 1 \) and \( g(-2) = -1 \) → not equal

4. For \( x = 6 \):

   • \( f(6) = -2 \) and doesn't exist in \( g(x) \) → not equal

5. For \( x = -12 \):

   • \( f(-12) = 3 \) and doesn't exist in \( g(x) \) → not equal

6. For \( x = 2 \):

   • doesn't exist in \( f(x) \) → not equal

7. For \( x = 1 \):

   • doesn't exist in \( f(x) \) → not equal

8. For \( x = 3 \):

   • doesn't exist in \( f(x) \) → not equal

From our evaluation, the only \( x \) values that overlap the output of \( f \) and \( g \) result in no matches.

Thus, based on the provided values from both tables, there are no common \( x \) values where \( f(x) = g(x) \), leading us to conclude:

The solution set is \( { } \) (an empty set).

If you are looking for explicitly asking to represent it in a specific format, such as {?,?}, we can simplify this to just \( {} \).