To solve for \( m\angle I \) and \( m\angle U \) in the inscribed quadrilateral \( AEIU \), we start with the given information:
- \( m\angle A = 27^\circ \)
- \( m\angle E = 2(m\angle A) = 2(27^\circ) = 54^\circ \)
In any cyclic quadrilateral (one inscribed in a circle), the opposite angles sum to \( 180^\circ \). This gives us the following relationships:
\[ m\angle A + m\angle I = 180^\circ \] \[ m\angle E + m\angle U = 180^\circ \]
Now substituting the known angles into these equations:
-
From \( m\angle A + m\angle I = 180^\circ \): \[ 27^\circ + m\angle I = 180^\circ \] \[ m\angle I = 180^\circ - 27^\circ = 153^\circ \]
-
From \( m\angle E + m\angle U = 180^\circ \): \[ 54^\circ + m\angle U = 180^\circ \] \[ m\angle U = 180^\circ - 54^\circ = 126^\circ \]
Thus, we have found the measures of the angles:
- \( m\angle I = 153^\circ \)
- \( m\angle U = 126^\circ \)
Therefore, the correct answer is:
\( m\angle I = 153^\circ \) and \( m\angle U = 126^\circ \).