To determine which type of wave has a higher frequency and which has higher energy, we can use the relationship between wavelength (λ), frequency (f), and energy (E).
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Frequency: The frequency of a wave is inversely proportional to its wavelength. The formula is given by: \[ c = f \cdot \lambda \] where \(c\) is the speed of light (approximately \(3 \times 10^8\) m/s).
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For AM waves with a wavelength of approximately 100 meters: \[ f_{AM} = \frac{c}{\lambda_{AM}} = \frac{3 \times 10^8 \text{ m/s}}{100 \text{ m}} = 3 \times 10^6 \text{ Hz} = 3 \text{ MHz} \]
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For FM waves with a wavelength of approximately 1 meter: \[ f_{FM} = \frac{c}{\lambda_{FM}} = \frac{3 \times 10^8 \text{ m/s}}{1 \text{ m}} = 3 \times 10^8 \text{ Hz} = 300 \text{ MHz} \]
Since \(3 \text{ MHz} < 300 \text{ MHz}\), FM has a higher frequency than AM.
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Energy: The energy of a photon is directly proportional to its frequency, represented by the formula: \[ E = h \cdot f \] where \(h\) is Planck's constant (\(6.626 \times 10^{-34} \text{ J s}\)).
Since FM waves have a higher frequency, they will also carry higher energy compared to AM waves.
In summary:
- FM has a higher frequency and higher energy than AM waves.
Thus, the correct response is: FM has a higher frequency and higher energy.
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