To find out how many times larger \( 9 \times 10^{-8} \) is than \( 3 \times 10^{-12} \), we divide the two numbers:
\[ \frac{9 \times 10^{-8}}{3 \times 10^{-12}} \]
First, divide the coefficients:
\[ \frac{9}{3} = 3 \]
Next, to handle the powers of 10, we apply the rule of exponents that states \( \frac{10^a}{10^b} = 10^{a-b} \):
\[ \frac{10^{-8}}{10^{-12}} = 10^{-8 - (-12)} = 10^{-8 + 12} = 10^{4} \]
Now, we combine the results:
\[ 3 \times 10^4 \]
Thus, \( 9 \times 10^{-8} \) is \( 3 \times 10^{4} \) times larger than \( 3 \times 10^{-12} \).
The correct response is:
3×10⁴ (3 times 10 to the 4th power)