Question
A student rides her bicycle down a hill. Together, she and the bicycle have a mass of 56 kilograms. She is moving at 11 meters per second. What is her kinetic energy?(1 point) Responses 17,248 J 17,248 J 3,388 J 3,388 J 13,552 J 13,552 J 6,776 J 6,776 J
Answers
GPT-4o mini
The formula for kinetic energy (KE) is given by:
\[
KE = \frac{1}{2} m v^2
\]
where \( m \) is the mass in kilograms and \( v \) is the velocity in meters per second.
Given:
- Mass \( m = 56 \) kg
- Velocity \( v = 11 \) m/s
Now, let's plug the values into the formula:
\[
KE = \frac{1}{2} \times 56 \, \text{kg} \times (11 \, \text{m/s})^2
\]
Calculating \( (11 \, \text{m/s})^2 \):
\[
(11 \, \text{m/s})^2 = 121 \, \text{m}^2/\text{s}^2
\]
Now substituting back:
\[
KE = \frac{1}{2} \times 56 \, \text{kg} \times 121 \, \text{m}^2/\text{s}^2
\]
\[
KE = 28 \times 121 \, \text{kg} \cdot \text{m}^2/\text{s}^2
\]
\[
KE = 3388 \, \text{J}
\]
Thus, the kinetic energy is **3,388 J**.
\[
KE = \frac{1}{2} m v^2
\]
where \( m \) is the mass in kilograms and \( v \) is the velocity in meters per second.
Given:
- Mass \( m = 56 \) kg
- Velocity \( v = 11 \) m/s
Now, let's plug the values into the formula:
\[
KE = \frac{1}{2} \times 56 \, \text{kg} \times (11 \, \text{m/s})^2
\]
Calculating \( (11 \, \text{m/s})^2 \):
\[
(11 \, \text{m/s})^2 = 121 \, \text{m}^2/\text{s}^2
\]
Now substituting back:
\[
KE = \frac{1}{2} \times 56 \, \text{kg} \times 121 \, \text{m}^2/\text{s}^2
\]
\[
KE = 28 \times 121 \, \text{kg} \cdot \text{m}^2/\text{s}^2
\]
\[
KE = 3388 \, \text{J}
\]
Thus, the kinetic energy is **3,388 J**.