Asked by Si
Hi,I have a linear model with equation p = 5.1t - 28, where p is the number of breeding pairs of birds and t is the year. I need to use algebra to find the year in which the linear model predicts the breeding pairs will exceed 500.
Any help appreciated.
Any help appreciated.
Answers
Answered by
drwls
Solve the equation
5.1t - 28 = 500
5.1t = 472
t = 472/5.1 = ___ years
Looks like a long wait.
I am assuming that "year zero" is the year when p = 28, and the counting starts. It is not 1 AD
5.1t - 28 = 500
5.1t = 472
t = 472/5.1 = ___ years
Looks like a long wait.
I am assuming that "year zero" is the year when p = 28, and the counting starts. It is not 1 AD
Answered by
Henry
Si, I'm assuming you meant the number of years it takes for the breeding pairs to exceed 500
P = 5.1t -28 = 500 Solve for t:
t = 528 / 5.1 = 103.5 or 104 yrs..
P = 5.1t -28 = 500 Solve for t:
t = 528 / 5.1 = 103.5 or 104 yrs..
Answered by
drwls
Yes. I agree with your answer.
Answered by
Henry
Thanks
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.