Question
What would the initial volume of. gas be if if started at 3atm and ended with a pressure of 7 ATM and a volume of 12 L
boyle law
boyle law
Answers
GPT-4o mini
Boyle's Law states that the pressure and volume of a gas are inversely proportional, as long as the temperature and the amount of gas remain constant. The formula for Boyle's Law is:
\[ P_1 V_1 = P_2 V_2 \]
Where:
- \( P_1 \) is the initial pressure,
- \( V_1 \) is the initial volume,
- \( P_2 \) is the final pressure,
- \( V_2 \) is the final volume.
You are given:
- \( P_1 = 3 \, \text{atm} \)
- \( P_2 = 7 \, \text{atm} \)
- \( V_2 = 12 \, \text{L} \)
You need to find \( V_1 \).
Rearranging the formula to solve for \( V_1 \):
\[ V_1 = \frac{P_2 V_2}{P_1} \]
Substituting in the known values:
\[ V_1 = \frac{(7 \, \text{atm}) \times (12 \, \text{L})}{3 \, \text{atm}} \]
Calculating:
\[ V_1 = \frac{84 \, \text{atm} \cdot \text{L}}{3 \, \text{atm}} = 28 \, \text{L} \]
So, the initial volume of the gas (\( V_1 \)) would be **28 liters**.
\[ P_1 V_1 = P_2 V_2 \]
Where:
- \( P_1 \) is the initial pressure,
- \( V_1 \) is the initial volume,
- \( P_2 \) is the final pressure,
- \( V_2 \) is the final volume.
You are given:
- \( P_1 = 3 \, \text{atm} \)
- \( P_2 = 7 \, \text{atm} \)
- \( V_2 = 12 \, \text{L} \)
You need to find \( V_1 \).
Rearranging the formula to solve for \( V_1 \):
\[ V_1 = \frac{P_2 V_2}{P_1} \]
Substituting in the known values:
\[ V_1 = \frac{(7 \, \text{atm}) \times (12 \, \text{L})}{3 \, \text{atm}} \]
Calculating:
\[ V_1 = \frac{84 \, \text{atm} \cdot \text{L}}{3 \, \text{atm}} = 28 \, \text{L} \]
So, the initial volume of the gas (\( V_1 \)) would be **28 liters**.