Question

What would the initial pressure of a gas be if if started at 30 L and ended with a. pressure of 4atm and volume of 45L.
boyle law

Answer 1

Boyle's Law states that the pressure of a gas is inversely proportional to its volume when the temperature is held constant. The equation representing Boyle's Law is:

\[
P_1 V_1 = P_2 V_2
\]

Where:
- \( P_1 \) is the initial pressure,
- \( V_1 \) is the initial volume,
- \( P_2 \) is the final pressure, and
- \( V_2 \) is the final volume.

From your question:

- \( V_1 = 30 \, \text{L} \)
- \( P_2 = 4 \, \text{atm} \)
- \( V_2 = 45 \, \text{L} \)

We need to find \( P_1 \). Rearranging the equation gives us:

\[
P_1 = \frac{P_2 V_2}{V_1}
\]

Substituting in the known values:

\[
P_1 = \frac{(4 \, \text{atm}) \times (45 \, \text{L})}{30 \, \text{L}}
\]

Calculating:

\[
P_1 = \frac{180}{30} = 6 \, \text{atm}
\]

Therefore, the initial pressure \( P_1 \) is **6 atm**.