Question
Express in simplest radical form.
start fraction, square root of, 12, end square root, divided by, square root of, 2, end square root, end fraction
2
12
Answer
Attempt 1 out of 5
start fraction, square root of, 12, end square root, divided by, square root of, 2, end square root, end fraction
2
12
Answer
Attempt 1 out of 5
Answers
GPT-4o mini
To simplify the expression \(\frac{\sqrt{12}}{\sqrt{2}}\), you can use the property of radicals that states \(\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}\).
So, we can rewrite the expression as:
\[
\frac{\sqrt{12}}{\sqrt{2}} = \sqrt{\frac{12}{2}} = \sqrt{6}
\]
Next, we simplify \(\sqrt{12}\) first, if needed:
\[
\sqrt{12} = \sqrt{4 \cdot 3} = \sqrt{4} \cdot \sqrt{3} = 2\sqrt{3}
\]
Now, substituting back into the expression:
\[
\frac{\sqrt{12}}{\sqrt{2}} = \frac{2\sqrt{3}}{\sqrt{2}} = 2\cdot\frac{\sqrt{3}}{\sqrt{2}} = 2\sqrt{\frac{3}{2}}
\]
But we'll use the first simplification for the simplest radical form which is:
\[
\sqrt{6}
\]
So, the final simplified answer is:
\[
\sqrt{6}
\]
So, we can rewrite the expression as:
\[
\frac{\sqrt{12}}{\sqrt{2}} = \sqrt{\frac{12}{2}} = \sqrt{6}
\]
Next, we simplify \(\sqrt{12}\) first, if needed:
\[
\sqrt{12} = \sqrt{4 \cdot 3} = \sqrt{4} \cdot \sqrt{3} = 2\sqrt{3}
\]
Now, substituting back into the expression:
\[
\frac{\sqrt{12}}{\sqrt{2}} = \frac{2\sqrt{3}}{\sqrt{2}} = 2\cdot\frac{\sqrt{3}}{\sqrt{2}} = 2\sqrt{\frac{3}{2}}
\]
But we'll use the first simplification for the simplest radical form which is:
\[
\sqrt{6}
\]
So, the final simplified answer is:
\[
\sqrt{6}
\]