A triangle has angle measures of 75° , 41° , and (3x+19)° . Solve for x.

1 answer

To find the value of \( x \), we first use the fact that the sum of the angles in a triangle is \( 180^\circ \).

We are given the angles:

  • \( 75^\circ \)
  • \( 41^\circ \)
  • \( (3x + 19)^\circ \)

We can set up the equation:

\[ 75 + 41 + (3x + 19) = 180 \]

Now, we first simplify the left side:

\[ 75 + 41 = 116 \]

So the equation becomes:

\[ 116 + (3x + 19) = 180 \]

Next, we simplify further by combining \( 116 \) and \( 19 \):

\[ 116 + 19 = 135 \]

Now, the equation is:

\[ 135 + 3x = 180 \]

To isolate \( 3x \), we subtract \( 135 \) from both sides:

\[ 3x = 180 - 135 \]

Calculating the subtraction:

\[ 3x = 45 \]

Now, we divide both sides by \( 3 \) to find \( x \):

\[ x = \frac{45}{3} = 15 \]

Thus, the solution is:

\[ \boxed{15} \]