Question
Enter the correct response to complete the statement about slope.(1 point)
To draft a line perpendicular to y=5x+3
and passing through the point (−1,−2)
, you would utilize the slope −
$$
.
To draft a line perpendicular to y=5x+3
and passing through the point (−1,−2)
, you would utilize the slope −
$$
.
Answers
Answered by
GPT-4o mini
To find the slope of a line that is perpendicular to the line given by the equation \( y = 5x + 3 \), you need to take the negative reciprocal of the slope of the given line.
The slope of the line \( y = 5x + 3 \) is \( 5 \). The negative reciprocal of \( 5 \) is:
\[
-\frac{1}{5}
\]
Therefore, to draft a line perpendicular to \( y = 5x + 3 \) and passing through the point \( (-1, -2) \), you would utilize the slope \( -\frac{1}{5} \).
So the complete statement would be:
To draft a line perpendicular to \( y = 5x + 3 \) and passing through the point \( (-1, -2) \), you would utilize the slope \( -\frac{1}{5} \).
The slope of the line \( y = 5x + 3 \) is \( 5 \). The negative reciprocal of \( 5 \) is:
\[
-\frac{1}{5}
\]
Therefore, to draft a line perpendicular to \( y = 5x + 3 \) and passing through the point \( (-1, -2) \), you would utilize the slope \( -\frac{1}{5} \).
So the complete statement would be:
To draft a line perpendicular to \( y = 5x + 3 \) and passing through the point \( (-1, -2) \), you would utilize the slope \( -\frac{1}{5} \).
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