Asked by Emoni
Two 2.4 cm diameter disks spaced 1.5 mm apart form a parallel-plate capacitor. The electric field between the disks is 4.3×10^5 V/m.
What is the voltage across the capacitor?
How much charge is on each disk?
An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.3×10^7 m/s. What was the electron's speed as it left the negative plate?
What is the voltage across the capacitor?
How much charge is on each disk?
An electron is launched from the negative plate. It strikes the positive plate at a speed of 2.3×10^7 m/s. What was the electron's speed as it left the negative plate?
Answers
Answered by
Drwls
E x d is the voltage
d is the plate separation
Use Gauss' Law or Q = CV for the charge
The change in kinetic energy equals e V
d is the plate separation
Use Gauss' Law or Q = CV for the charge
The change in kinetic energy equals e V
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