Asked by kamleen
from an ordinary deck of 52 cards, a single card is selected random. what is the probability that it is a 10 or red card?
Answers
Answered by
Reiny
prob(10 or red)
= prob(10) + prob(red) - prob(10 AND red)
= 4/52 + 26/52 - 2/52
= 28/52
= 7/13
= prob(10) + prob(red) - prob(10 AND red)
= 4/52 + 26/52 - 2/52
= 28/52
= 7/13
Answered by
Vixia
From an ordinary deck of 52 cards, a single card is selected random. What is the probability that it is a 10 or red card?
= prob(10) + prob(red) - prob(10 AND red)
= 4/52 + 26/52 - 2/52
= 28/52
= 7/13
So, the answer is 7/13.
Credits go to Reiny for helping.
= prob(10) + prob(red) - prob(10 AND red)
= 4/52 + 26/52 - 2/52
= 28/52
= 7/13
So, the answer is 7/13.
Credits go to Reiny for helping.
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