Question

The function pictured has the form of y=k(x^2). What is the value of k?
(-4,4)(-2,1)(2,1)(4,4)

(1 point)
Responses

1/4
1 fourth

1
1

2
2

1/2

Answer 1

To find the value of \( k \) in the equation \( y = kx^2 \), we can use one of the points given.

Let's use the point \( (-2, 1) \):

1. Substitute \( x = -2 \) and \( y = 1 \) into the equation:
\[
1 = k(-2)^2
\]

2. Calculate \( (-2)^2 \):
\[
(-2)^2 = 4
\]
Thus, the equation becomes:
\[
1 = 4k
\]

3. Solve for \( k \):
\[
k = \frac{1}{4}
\]

So, the value of \( k \) is \( \frac{1}{4} \).

The correct response is \( \frac{1}{4} \) or "1 fourth".