Linear Expressions, Equations, & Inequalities Portfolio Worksheet
1. Bear Population Study
a. Rewrite the bear population in Year 3 using the Distributive Property:
\[ 2(x + 10) = 2x + 20 \]
So, the bear population in Year 3 is \(2x + 20\).
b. The total number of bears in the park during Year 2 is 42. To find the number of bears in Year 1:
Given Year 2: \(x + 10 = 42\)
Solve for \(x\): \[ x + 10 = 42 \] \[ x = 42 - 10 \] \[ x = 32 \]
Answer: There were 32 bears in the park during Year 1. This means that the population increased by 10 in Year 2.
c. The total number of bears in the park during Year 3 is 50. To find the number of bears in Year 1:
Given Year 3: \(2(x + 10) = 50\)
Solve for \(x\): \[ 2(x + 10) = 50 \] \[ x + 10 = 25 \] \[ x = 25 - 10 \] \[ x = 15 \]
Answer: There were 15 bears in the park during Year 1. This is different from part b because the growth in population may vary based on different yearly recordings or growth rates.
d. Solve the inequality \(y + 5 > 38\):
\[ y + 5 > 38 \] \[ y > 38 - 5 \] \[ y > 33 \]
Three possible values for \(y\): 34, 35, and 36.
2. Wolf Population Study
a. Write and solve a linear equation for the number of wolves:
Set Year 2 equal to Year 3: \[ 7 + z = 3z - 3 \]
Solve for \(z\): \[ 7 + z + 3 = 3z \] \[ 10 = 3z - z \] \[ 10 = 2z \] \[ z = 5 \]
Answer: The value of \(z\) is 5, meaning there were 5 wolves in Year 1.
b. To write an expression for the number of wolves in Year 4, we can choose \(a = 3\) and \(b = 4\), leading to the expression:
\[ (x + 3)(x - 4) \]
Multiplying the two terms: \[ x^2 - 4x + 3x - 12 = x^2 - x - 12 \]
Final expression for Year 4: \(x^2 - x - 12\) (the number of wolves in Year 4).
Make sure to fill in any additional details or specific formatting as required by your instructor before submitting the worksheet.