To solve for the angles of the cyclic quadrilateral \( AEIU \) inscribed in circle \( O \), we can use the fact that the opposite angles of a cyclic quadrilateral add up to \( 180^\circ \).
Given:
- \( m\angle A = 27^\circ \)
- \( m\angle E = 2(m\angle A) = 2 \times 27^\circ = 54^\circ \)
Now, we can find \( m\angle I \) and \( m\angle U \) using the property of the cyclic quadrilateral:
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Since \( m\angle A + m\angle I = 180^\circ \): \[ m\angle I = 180^\circ - m\angle A = 180^\circ - 27^\circ = 153^\circ \]
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Since \( m\angle E + m\angle U = 180^\circ \): \[ m\angle U = 180^\circ - m\angle E = 180^\circ - 54^\circ = 126^\circ \]
Therefore, we find:
- \( m\angle I = 153^\circ \)
- \( m\angle U = 126^\circ \)
So the correct response is: m∠I=153° and m∠U=126°.