Asked by JT
3m^3 + 27m = 3m(m^2 + 9)
= 3m(m + 3)(m – 3)
I miss something? is this complete?
= 3m(m + 3)(m – 3)
I miss something? is this complete?
Answers
Answered by
Reiny
Your final answer is incorrect
stop at
3m(m^2 + 9)
we cannot factor the SUM of squares, only the difference of squares.
Had it been 3m^3 - 27m , your final would have been correct.
stop at
3m(m^2 + 9)
we cannot factor the SUM of squares, only the difference of squares.
Had it been 3m^3 - 27m , your final would have been correct.
Answered by
Carol
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