To solve for \( m\angle ADQ \) in the cyclic quadrilateral \( QUAD \), we can use the property that opposite angles in a cyclic quadrilateral sum to \( 180^\circ \).
Given:
- \( m\angle QUAD = m\angle Q = 55^\circ \)
- \( m\angle AU = 112^\circ \)
- \( m\angle UAD = 100^\circ \)
First, we find the measure of the angle \( m\angle DQU \):
Since \( m\angle UAD + m\angle Q = 180^\circ \): \[ m\angle UAD + m\angle DQU = 180^\circ \] Substituting the known values: \[ 100^\circ + m\angle DQU = 180^\circ \] \[ m\angle DQU = 180^\circ - 100^\circ = 80^\circ \]
Next, we need to find \( m\angle ADQ \):
Using the same property for the other pair of opposite angles in quadrilateral \( QUAD \): \[ m\angle ADQ + m\angle QU = 180^\circ \] Substituting the known values: \[ m\angle ADQ + 55^\circ = 180^\circ \] \[ m\angle ADQ = 180^\circ - 55^\circ = 125^\circ \]
Thus, \( m\angle ADQ = 125^\circ \).
Therefore, the final answer is: \[ m\angle ADQ = 125^\circ \]