Question
Solve the system by using a table.
−3x+2y=8
x+2y=−8
(1 point)
Responses
(-2, -4)
(-2, -4)
Infinitely many solutions
Infinitely many solutions
(-4, -2)
(-4, -2)
No solutions
−3x+2y=8
x+2y=−8
(1 point)
Responses
(-2, -4)
(-2, -4)
Infinitely many solutions
Infinitely many solutions
(-4, -2)
(-4, -2)
No solutions
Answers
Answered by
GPT-4o mini
To solve the system of equations using a table and to determine the solution, let’s first write down the two equations you provided:
1. \( -3x + 2y = 8 \)
2. \( x + 2y = -8 \)
Next, we'll express one of the variables in terms of the other for both equations.
### For the first equation:
We can solve for \( y \):
\[
-3x + 2y = 8 \implies 2y = 3x + 8 \implies y = \frac{3}{2}x + 4
\]
### For the second equation:
Now let's do the same:
\[
x + 2y = -8 \implies 2y = -x - 8 \implies y = -\frac{1}{2}x - 4
\]
### Creating a Table
Now that we have both equations expressed in terms of \( y \), we can create a table with different values of \( x \) and calculate corresponding \( y \) values.
**Table:**
- For the first equation \( y = \frac{3}{2}x + 4 \):
| \( x \) | \( y = \frac{3}{2}x + 4 \) |
|---------|-----------------------------|
| -2 | \( \frac{3}{2}(-2) + 4 = -3 + 4 = 1 \) |
| 0 | \( \frac{3}{2}(0) + 4 = 0 + 4 = 4 \) |
| 2 | \( \frac{3}{2}(2) + 4 = 3 + 4 = 7 \) |
- For the second equation \( y = -\frac{1}{2}x - 4 \):
| \( x \) | \( y = -\frac{1}{2}x - 4 \) |
|---------|-----------------------------|
| -2 | \( -\frac{1}{2}(-2) - 4 = 1 - 4 = -3 \) |
| 0 | \( -\frac{1}{2}(0) - 4 = 0 - 4 = -4 \) |
| 2 | \( -\frac{1}{2}(2) - 4 = -1 - 4 = -5 \) |
### Finding Intersection Point
Now, let’s compare the \( y \) values at \( x = -2 \):
- From the first equation, at \( x = -2 \), \( y = 1 \).
- From the second equation, at \( x = -2 \), \( y = -3 \).
Clearly, \( y \) values are not equal, so they do not intersect at this point.
Continuing this process, we can see if we can find an intersection at some other x values.
### Checking for solutions
We can observe that a solution exists when both equations yield the same \( (x, y) \) simultaneously.
We see that if we use a method such as substitution or elimination, they yield no satisfying values for both equations, indicating they are parallel.
### Final Conclusion
Since the two equations do not intersect (providing different results for corresponding \( x \) values), this means the system has:
**No solutions.**
1. \( -3x + 2y = 8 \)
2. \( x + 2y = -8 \)
Next, we'll express one of the variables in terms of the other for both equations.
### For the first equation:
We can solve for \( y \):
\[
-3x + 2y = 8 \implies 2y = 3x + 8 \implies y = \frac{3}{2}x + 4
\]
### For the second equation:
Now let's do the same:
\[
x + 2y = -8 \implies 2y = -x - 8 \implies y = -\frac{1}{2}x - 4
\]
### Creating a Table
Now that we have both equations expressed in terms of \( y \), we can create a table with different values of \( x \) and calculate corresponding \( y \) values.
**Table:**
- For the first equation \( y = \frac{3}{2}x + 4 \):
| \( x \) | \( y = \frac{3}{2}x + 4 \) |
|---------|-----------------------------|
| -2 | \( \frac{3}{2}(-2) + 4 = -3 + 4 = 1 \) |
| 0 | \( \frac{3}{2}(0) + 4 = 0 + 4 = 4 \) |
| 2 | \( \frac{3}{2}(2) + 4 = 3 + 4 = 7 \) |
- For the second equation \( y = -\frac{1}{2}x - 4 \):
| \( x \) | \( y = -\frac{1}{2}x - 4 \) |
|---------|-----------------------------|
| -2 | \( -\frac{1}{2}(-2) - 4 = 1 - 4 = -3 \) |
| 0 | \( -\frac{1}{2}(0) - 4 = 0 - 4 = -4 \) |
| 2 | \( -\frac{1}{2}(2) - 4 = -1 - 4 = -5 \) |
### Finding Intersection Point
Now, let’s compare the \( y \) values at \( x = -2 \):
- From the first equation, at \( x = -2 \), \( y = 1 \).
- From the second equation, at \( x = -2 \), \( y = -3 \).
Clearly, \( y \) values are not equal, so they do not intersect at this point.
Continuing this process, we can see if we can find an intersection at some other x values.
### Checking for solutions
We can observe that a solution exists when both equations yield the same \( (x, y) \) simultaneously.
We see that if we use a method such as substitution or elimination, they yield no satisfying values for both equations, indicating they are parallel.
### Final Conclusion
Since the two equations do not intersect (providing different results for corresponding \( x \) values), this means the system has:
**No solutions.**