Question

A sample of iron weighing 111.6 g was subjected to heating, experiencing a temperature increase from 0°C to 20°C. The sample absorbed a total of 1004 J of energy during this process. What is the specific heat capacity of iron?(1 point)
Responses

0.00578 J/g°C
0.00578 J/g°C

0.45 J/g°C
0.45 J/g°C

4.18 J/g°C
4.18 J/g°C

2.20 J/g°C

Answer 1

To find the specific heat capacity (c) of iron, we can use the formula:

\[
q = m \cdot c \cdot \Delta T
\]

where:
- \(q\) = heat absorbed (in joules)
- \(m\) = mass of the sample (in grams)
- \(c\) = specific heat capacity (in J/g°C)
- \(\Delta T\) = change in temperature (in °C)

Given:
- \(q = 1004 \, J\)
- \(m = 111.6 \, g\)
- \(\Delta T = 20°C - 0°C = 20°C\)

We rearrange the formula to solve for \(c\):

\[
c = \frac{q}{m \cdot \Delta T}
\]

Substituting in the given values:

\[
c = \frac{1004 \, J}{111.6 \, g \cdot 20 \, °C}
\]

Calculating the denominator:

\[
m \cdot \Delta T = 111.6 \, g \cdot 20 \, °C = 2232 \, g°C
\]

Now, substituting this back into the equation for \(c\):

\[
c = \frac{1004 \, J}{2232 \, g°C} \approx 0.450 \, J/g°C
\]

Thus, the specific heat capacity of iron is approximately **0.45 J/g°C**.

The correct response is:

**0.45 J/g°C**.