Question
What potential energy is acquired by a hammer with a mass of 0.75 kg when raised 0.35 m?
(1 point)
Responses
2.58 joules
2.58 joules
0.2625 joules
0.2625 joules
2.14 joules
2.14 joules
0 Newtons
0 Newtons
2.34 Newtons
(1 point)
Responses
2.58 joules
2.58 joules
0.2625 joules
0.2625 joules
2.14 joules
2.14 joules
0 Newtons
0 Newtons
2.34 Newtons
Answers
Answered by
GPT-4o mini
The potential energy (PE) acquired by an object when raised to a height can be calculated using the formula:
\[
PE = mgh
\]
where:
- \(m\) is the mass of the object (in kg),
- \(g\) is the acceleration due to gravity (approximately \(9.81 \, \text{m/s}^2\) on Earth), and
- \(h\) is the height raised (in meters).
Given:
- \(m = 0.75 \, \text{kg}\)
- \(g = 9.81 \, \text{m/s}^2\)
- \(h = 0.35 \, \text{m}\)
Now calculating:
\[
PE = 0.75 \, \text{kg} \times 9.81 \, \text{m/s}^2 \times 0.35 \, \text{m}
\]
\[
PE = 0.75 \times 9.81 \times 0.35
\]
\[
PE \approx 0.75 \times 3.4335 \approx 2.577625 \, \text{joules}
\]
Rounding this to two decimal places gives approximately \(2.58 \, \text{joules}\).
Therefore, the correct response is:
**2.58 joules**
\[
PE = mgh
\]
where:
- \(m\) is the mass of the object (in kg),
- \(g\) is the acceleration due to gravity (approximately \(9.81 \, \text{m/s}^2\) on Earth), and
- \(h\) is the height raised (in meters).
Given:
- \(m = 0.75 \, \text{kg}\)
- \(g = 9.81 \, \text{m/s}^2\)
- \(h = 0.35 \, \text{m}\)
Now calculating:
\[
PE = 0.75 \, \text{kg} \times 9.81 \, \text{m/s}^2 \times 0.35 \, \text{m}
\]
\[
PE = 0.75 \times 9.81 \times 0.35
\]
\[
PE \approx 0.75 \times 3.4335 \approx 2.577625 \, \text{joules}
\]
Rounding this to two decimal places gives approximately \(2.58 \, \text{joules}\).
Therefore, the correct response is:
**2.58 joules**