Question
consider a different DNA molecule if 15% of the bases are cytosine what percentage of the bases would be adenine
15%
30%
35%
70%
15%
30%
35%
70%
Answers
GPT-4o mini
In a DNA molecule, the amount of adenine (A) is equal to the amount of thymine (T), and the amount of cytosine (C) is equal to the amount of guanine (G). This is known as Chargaff's rule.
If 15% of the bases are cytosine (C), then 15% of the bases will also be guanine (G). This accounts for 30% of the total bases (15% C + 15% G).
Since the total percentage of all four bases (A, T, C, G) is 100%, we can find the remaining percentage to be divided between adenine and thymine:
100% - 30% (C + G) = 70%
The remaining 70% will be equally split between adenine and thymine, so:
Adenine (A) = 70% / 2 = 35%
Thymine (T) = 70% / 2 = 35%
Thus, the percentage of adenine in this DNA molecule would be **35%**.
If 15% of the bases are cytosine (C), then 15% of the bases will also be guanine (G). This accounts for 30% of the total bases (15% C + 15% G).
Since the total percentage of all four bases (A, T, C, G) is 100%, we can find the remaining percentage to be divided between adenine and thymine:
100% - 30% (C + G) = 70%
The remaining 70% will be equally split between adenine and thymine, so:
Adenine (A) = 70% / 2 = 35%
Thymine (T) = 70% / 2 = 35%
Thus, the percentage of adenine in this DNA molecule would be **35%**.