To find the area of triangle \( ABC \) using the formula
\[ A = \frac{1}{2}ab \sin C, \]
we need to plug in the values for \( a \), \( b \), and \( \angle C \).
Given:
- \( a = 6 \) yards
- \( b = 12 \) yards
- \( \angle C = 48^\circ \)
Now, we calculate \( \sin C \):
\[ \sin(48^\circ) \approx 0.7431 , (\text{using a calculator}) \]
Now we can plug in the values into the area formula:
\[ A = \frac{1}{2} \times 6 \times 12 \times \sin(48^\circ) \]
Calculating it step by step:
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Calculate \( \frac{1}{2} \times 6 \times 12 \): \[ \frac{1}{2} \times 6 \times 12 = \frac{72}{2} = 36 \]
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Now multiply by \( \sin(48^\circ) \): \[ A = 36 \times 0.7431 \approx 26.70 \]
Rounding to the nearest square yard, the area \( A \) is approximately \( 27 \) square yards.
Thus, the answer is:
27 yards² (or 27 yards squared).